Question

A cone-shaped funnel has a diameter of 3.6 in. and a height of 3 in. What is the volume of the funnel? Enter your answer as a decimal in the box. Use 3.14 for pi.

Answer 1

V=1/3πr^2h
d=3.6 in.
r=1.8 in.
V=1/3×π×1.8^2×3
V≈10.1736 cubic inches. As a result, the volume of the funnel is 10.1736 cubic inches. Hope it help!

Answer 2

The volume of the given cone is 10.17 in ^3.

How to get the volume of the cone?

We know that for a cone of radius R and height H, the volume is:

V = (1/3)*3.14*R^2*H

In this case, we know that the diameter is 3 in, and the radius is half of that, then:

R = (3.6 in)/2 =  1.8 in

And the height is 3 in.

So the volume is:

V = (1/3)*3.14*(1.8 in)^2*(3 in) = 10.17 in ^3

If you want to learn more about volumes, you can read:

https://brainly.com/question/1972490