Respuesta :
we know that
[tex]C = \frac{5}{9}(F-32)\\ \\F=\frac{9}{5}C+32[/tex]
Step [tex]1[/tex]
Find the inequality
we know that
[tex]C = \frac{5}{9}(F-32)[/tex] --------> equation [tex]1[/tex]
and
[tex]-30\° < C < 130\°[/tex]
substitute the equation [tex]1[/tex] in the inequality
[tex]-30\° < \frac{5}{9}(F-32) < 130\°[/tex]
Step [tex]2[/tex]
Convert [tex]-30\°C[/tex] to F
substitute in the formula
[tex]F=\frac{9}{5}*(-30)+32\\ \\F= -22\°[/tex]
Step [tex]3[/tex]
Convert [tex]130\°C[/tex] to F
substitute in the formula
[tex]F=\frac{9}{5}*(130)+32\\ \\F= 266\°[/tex]
therefore
[tex]-22\° < F < 266\°[/tex]
the answer is the option
B. −30 < 5 over 9 (F − 32) < 130; −22 < F < 266