Question

A sample of 4 different calculators is randomly selected from a group containing 16 that are defective and 30 that have no defects. What is the probability that at least one of the calculators is defective

0.168
0.160
0.819
0.832

Answer 1

The solution would be like this for this specific problem:

$( \frac{30}{46}) * ( \frac{29}{45}) * ( \frac{28}{44}) *( \frac{27}{43}) = 0.168$

 

The probability that at least one of the 4 calculators in the sample is defective is complement of 0.168 so the answer is 0.832.

Answer 2

Answer:

.832

Step-by-step explanation: