Answer:
[tex]x=-\frac{5}{4}[/tex]
Step-by-step explanation:
Given equation,
[tex]y^2=5x-----(1)[/tex]
Which is the equation of a parabola along x-axis,
From equation (1),
[tex](y-0)^2=\frac{4}{4}\times 5(x-0)[/tex]
[tex](y-0)^2=4(\frac{5}{4})(x-0)-----(2)[/tex]
We know that, the standard form of a parabola along x-axis is,
[tex](y-k)^2=4p(x-h)[/tex]
Where, the directrix is,
x = h-p
By comparing equation (2),
The directrix of the given parabola is,
[tex]x = 0 - \frac{5}{4}\implies x = -\frac{5}{4}[/tex]