Question

A football team played A games last year. They lost B of those games. What was their winning percentage? 

    (100)B/A

    A(100)/B

    (A-B) /A x 100

    B-A(100)/B

    A-B(100)/A(10)

Answer 1

winning%=100[wins/(total games)]

w%=100(A-B)/A

So the way that your choice expressed that is:

(A-B)/A x 100

Answer 2

As per linear equation, the percentage of games the football team won is [(A - B)/A] x 100.

What  is a linear equation?

A linear equation is an equation that contains one or multiple variable with the highest power of the variable is one.

Given, a football team played 'A' games last year.

They lost 'B' of those games.

Therefore, the football team won (A - B) games.

The percentage of games the football team won is

= [(A - B)/A] x 100

Learn more about linear equation here: https://brainly.com/question/14323386

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