Question

Two boys are throwing a baseball back and forth. The ball is 4 ft above the ground when it leaves one child’s hand with an upward velocity of 36 ft/s. If acceleration due to gravity is –16 ft/s2, how high above the ground is the ball 2 s after it is thrown?

Answer 1

the answer is a 12ft

Answer 2

Answer:

The ball is about $44 ft$ above the ground

Step-by-step explanation:

As per newton's second law of motion

$S = ut + \frac{1}{2} at^2$

Substituting the given values in above equation, we get -

$S = (36)(2) + \frac{1}{2} (-16)(2^2)\\= 40 ft$

The total height including the height of ball from where it is throws

$40 ft  + 4 ft\\= 44 ft$