angie176 angie176

16-05-2017
Chemistry

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How many atoms are present In 179.0 g of irídium

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davinioza davinioza

16-05-2017

179.0 g of iridium (1 mol / 192.217 g) ( 6.022 x 10^23 atoms / 1 mol ) = 5.61 x 10^23 atoms of iridium

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