Question

Cromwell Field is located at(2.5,3.5) and Dedeaux Field is located at (1.5,4.5) on a map. If each map unit is 0.1 mile, about how far apart are the fields?

Answer 1

You can apply the distance between points formula.

D =√[(diff. of x-coord.)² +(diff. of y-coord.)²]

D = √(2.5 -1.5)² +(3.5-4.5)²

D = √[1² +(-1)²] =  √2

D ≈ 1.14142 units

Multiply by 0.1 mile

D = 1.14142 * 0.1 = 0.14142

D≈0.141 miles

Answer 2

The distance between the two fields Cromwell Field is located at(2.5,3.5) and Dedeaux Field is located at (1.5,4.5) will be 0.1414 miles.

What is the distance between two points ( p,q) and (x,y)?

The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

D = √[(x-p)² + (y-q)²] units

The distance between the Cromwell Field(2.5,3.5) and Dedeaux Field(1.5,4.5) will be,

$\rm Distance = \sqrt{(2.5-1.5)^2+(3.5-4.5)^2} = \sqrt{(1)^2+(-1)^2} = \sqrt2 = 1.414$

Since a map unit is 0.1 mile, the distance between two fields will be,

Distance = 1.414 × 0.1 miles = 0.1414 miles

Hence, the distance between the two fields will be 0.1414 miles.

Learn more about the Distance between two points:

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