Answer:
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Step-by-step explanation:
We know that value of [tex]cos\dfrac{3\pi}{2}=0[/tex]
Also, secx=1/cosx
Hence, [tex]sec\dfrac{3\pi}{2}=\dfrac{1}{cos\dfrac{3\pi}{2}}[/tex]
This implies [tex]sec\dfrac{3\pi}{2}=\dfrac{1}{0}[/tex]
i.e. sec3π/2 is undefined