Respuesta :
first integer: x
second integer: x+1
third integer: x+2
Set up an equation: 3x+3=243
3x=240
x=80
The integers are 80,81,82
second integer: x+1
third integer: x+2
Set up an equation: 3x+3=243
3x=240
x=80
The integers are 80,81,82
Three consecutive integers are n, n+1, and n+2 so
n+n+1+n+2=243
3n+3=243
3n=240
n=80
So the integers are 80,81, and 82
n+n+1+n+2=243
3n+3=243
3n=240
n=80
So the integers are 80,81, and 82