As points, x-intercepts take the form [tex](x,0)[/tex], so to find the intercepts we can set [tex]y=0[/tex] and solve for [tex]x[/tex].
[tex]x\ln(x+e)=0\implies\begin{cases}x=0\\\ln(x+e)=0\end{cases}[/tex]
From the first equation alone, we already know that [tex]x=0[/tex] is a solution, which means one intercept is [tex](0,0)[/tex].
The second equation gives
[tex]\ln(x+e)=0\implies e^{\ln(x+e)}=e^0\implies x+e=1\implies x=1-e[/tex]
so that the second intercept occurs at [tex](1-e,0)[/tex].
So if [tex]a=0[/tex] and [tex]b=1-e[/tex], we have [tex]a+b=1-e[/tex], giving C as the answer.