Answer:
[tex]\frac{x^2}{14^2} +\frac{y^2}{10^2} =1[/tex]
Step-by-step explanation:
Given is the equation of an ellipse in standard form.
Centre is at the origin.
So ellipse would have equation as
[tex]\frac{x^2}{a^2} +\frac{y^2}{b^2} =1[/tex]
To find a and b:
Since width is more than height this is horizontal ellipse with a>b
2a = width= 28 ft
2b = height =20 ft
a = 14 ft, b = 10 ft
[tex]\frac{x^2}{14^2} +\frac{y^2}{10^2} =1[/tex]