Question

How does the value of Ka and Kb compare with the concentrations of hydronium ion and hydroxide ion?
Ka X Kb= [H3O+][OH-]
Ka X Kb> [H3O+][OH-]
Ka X Kb< [H3O+]+[OH-]
Ka X Kb+ [H3O]/[OH-]

Answer 1

Assuming that we are given the values of Ka and Kb, these can be rewritten and represented by the concentration of the Hydronium ion and Hydroxide Ion:

Hydronium ion: [H3O+]
Hydroxide ion: [OH-]

Ka is the equilibrium constant of an acid which dissociates to a hydronium ion and its cation.
Kb is the equilibrium constant of a base which dissociates to a hydroxide ion and its anion. 

So,

Ka x Kb = [H3O+][OH-]

Answer 2

Answer:

The correct answer is A, Ka × Kb = [H₃0⁺][OH⁻]

I hope this helps, have a good day and good luck! :)