Question

I have to factor this trinomial: n to the second power plus 2n minus 48. What is the answer?

Answer 1

n^2+2n-48 (n+8) (n-6) explanation -48 tells me the signs of the numbers are different and that I must subtract two numbers multiplied = 48 subtracted = +2 +8. and -6

Answer 2

$n^2+2n-48=n^2+8n-6n-48\\\\=n\cdot n+n\cdot8-6\cdot n-6\cdot8\\\\=n(n+8)-6(n+8)\\\\=\boxed{(n+8)(n-6)}$