2x+y=6
y=6-2x and y=x^2-4x+3
The solution occurs when they are equal so we can say y=y which is:
x^2-4x+3=6-2x add 2x to both sides
x^2-2x+3=6 subtract 6 from both sides
x^2-2x-3=0 factor
(x+1)(x-3)=0
So x=-1 and 3, using y=6-2x we find the corresponding y values...
y(-1)=6--2=8, y(3)=6-6=0 so the two solutions are the points:
(-1,8) and (3,0)
