Answer:
Option b is right
Step-by-step explanation:
Sample size =100
p = sample proportion of computer winning = 0.9
q = sample proportion of computer not winning = 0.1
P = the population proportion
If equally likely then P = 0.5
H0: p =0.5
Ha: p>0.5
(One tailed test)
Test statistic = [tex]\frac{p-P}{\sqrt{\frac{pq}{n} } } \\=\frac{0.4}{0.03} \\=13.33[/tex]
Since this lies outside 1.96 we reject null hypothesis
i.e. computer will always win in a competition against humna
Option b is right