Question

Calculate the mass of NaCl required to prepare 0.5 liters of a 2.5 molar solution of NaCl.

11
Na
22.99
Sodium


17
Cl
35.45
Chlorine

A. 37.1 g
B. 54.7 g
C. 73.1 g
D. 112.1 g

Answer 1

The answer is C. Here is the work:

Moles=molarity * volume
2.5 * 0.5 = 1.25mols of NaCI
Mm of NaCI= 58.442468/mol
Multiply the moles by the Mm and you get the grams
1.25 * 58.442468 =73.1g