Question

An isosceles trapezoid has base angles of 45° and bases of lengths 9 and 15. The area of the trapezoid is

Answer 1

tangent 45 = height / 3
height = 3 * tan (45)
height = 3 * 1
height = 3

Trapezoid area = ((sum of the bases) ÷ 2) • height

Trapezoid area =  (9 + 15) /2 * height

Trapezoid area =  12 * 3

Trapezoid area =  36

Answer 2

The area of the trapezoid is 36 square units if the isosceles trapezoid has base angles of 45° and bases of lengths 9 and 15.

What is a trapezoid?

It is defined as the quadrilateral having four sides in which two sides are parallel to each other, it is a 2-dimensional geometry.

Figure is attached in the picture, please refer to the figure.

From the figure:

tan45 = h/3

h = 3

The are of the trapezoid  = [(a+b)/2]×h

= [(9+15)/2]×3

Trapezoid area =  36 square units

Thus, the area of the trapezoid is 36 square units if the isosceles trapezoid has base angles of 45° and bases of lengths 9 and 15.

Learn more about the trapezoid here:

brainly.com/question/8643562

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