Question

How many atoms and molecules are present in 124 gram of phosphorus

Answer 1

31g phosphorus has 6.02×10^23 atoms
then 124 "          ''      (6.02×10^23×124)÷31
                                 ≈2.408×10^24
and molecules are (2.408×10^24×2)
                             ≈4.816×10^24