If a 35 year old women has averaged 8 hours of sleep each 24 hours, how many days of her life has she spent sleeping?

Respuesta :

mjatac
8*365= 2920
2920*35= 102200
102200/24= approx. 4,258.33 days 
35 years
1year=365 days, 35/4= 11.xx. Since its under 36, add 11 days because of the leap year every 4 years. (35x365)+11.
=12786. Now since these are the total days, divide it by 3 since 8hours/24 hours is 1/3. And you get 4262 hours of sleep in her 35 years of life.