Respuesta :
Below are the steps that need to be performed to this expression to obtain the correct answer.
[tex](\frac{x^{12}}{x^{-3}})^{5}\\=\frac{x^{60}}{x^{-15}} \\= x^{60+15}\\=x^{75}[/tex]
If, instead of multiply the exponents of both the numerator and denominator by 5 before proceeding, you divide the exponents and then multiply by 5, you will obtain:
[tex](\frac{x^{12}}{x^{-3}})^{5} \\=(x^{12/-3})^{5}\\=(x^{-4})^{5}\\=x^{-20}[/tex]
Which can be written, in positive exponents, as
[tex]\frac{1}{x^{20}}[/tex].
So Blake's mistake is that he divided the exponents inside the parenthesis before proceeding. Answer choice D is the right answer.
ANSWER: D