Question

2. A gas has a pressure of 0.410 atm and a volume of 32 L. At what pressure would the volume of
the gas change to 28L?

Answer 1

For this item, we assume that the gas behaves ideally such that it follows the ideal gas law and the ideal gas equation is applicable.
                                    PV = nRT 
where P is pressure, V is volume, n is number of moles, R is universal gas constant, and T is temperature. When the right-hand side of the equation is constant, there exist a relationship that,
                                    P₁V₁ = P₂V₂
Substituting the given,
                                 (0.410 atm)(32 L) = (P₂)(28 L)
The value of P₂ is equal to 0.4686 atm.