Answer: 1. 7
2. 100
3. 193.8
4. 0.8
5. 90.6
Step-by-step explanation:
1. Given the data 9,3,10,12,4,5,12,2
For finding the median we arrange it in ascending order
2,3,4,5,9, 10,12,12
Since the no of observations are even
∴ median =[tex]\frac{n/2 th term + (n/2 + 1)th term}{2}[/tex]
= [tex]\frac{5+9}{2}[/tex]
=[tex]\frac{14}{2}[/tex]
=7
i.e. Median =7
2. Given the data
23, 95,100,23,100,100
Since the no 100 is repeated thrice i.e. the maximum no of times
∴ Mode=100
3.
Given the data
108, 305,252,113, 191
Mean=[tex]\frac{108+305+252+113+191}{5}[/tex]
=[tex]\frac{969}{5}[/tex]
=193.8
4. Money spent in the first week
= $11.52, $6.48, $5.99, $14.00, and $9.50
Total for the first week
=11.52+6.48+5.99+14.00+9.50
=$47.49
Now she spent $4 more in the second week
i.e.$47.49+4
=51.49$
Increase in mean =[tex]\frac{4}{5}[/tex]
=0.8
5.
Given
2 students scored 100 each
9 students scored 95 each
10 students scored 90 each
3 students scored 80 each
1 student scored 70
Total score of students =[tex]2\times100+ 9\times 95+10\times90+3\times80+70\times1[/tex]
=2265
The average score
=[tex]\frac{2265}{25}[/tex]
=90.6
