Question

Average speed of Car 1 = 55 mph. Average speed of Car 2 = 70 mph. Time elapsed between start of Car 1 and start of Car 2 = 4 minutes. How long before Car 2 overtakes Car 1? hour =

Answer 1

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose car 2 overtakes car 1 at distance d in t hrs after car 1 moves.

So, distance covered by car 1 in t hrs will be :

$distance = speed*time$

$d=55*t = 55t$

distance covered by car 2 will take 4 minutes less that car 1, so time will be

$(t-\frac{4}{60})=(t-0.067)$

So, distance covered by car 2 will be:

$d = 70*(t-0.067) = 70t - 4.69$

Both distance will be same for overtaking, so

$55t = 70t-4.69$

$15t = 4.69$

$t =0.31 hrs$

It will take 0.31 hrs to overtake car 1   :   Answer

Hope it will help :)

Answer 2

answer:

Average speed of Car 1 = 55 mph. Average speed of Car 2 = 70 mph. Time elapsed between start of Car 1 and start of Car 2 = 4 minutes. How long before Car 2 overtakes Car 1? hour = 0.24 hours