Respuesta :
Slope= rise/run
= change in y / change in x
= y - y₂/ x-x₂
R(-1, 1), S(2, 4), T(6, 8)
Using points S and T -------(x,y)
S: y=4, x=2
T: y₂=8, x₂=6
Then insert into
Slope=y - y₂/ x-x₂
= 4 - 8/ 2-6
= -4/-4
= 1
The slope is one
= change in y / change in x
= y - y₂/ x-x₂
R(-1, 1), S(2, 4), T(6, 8)
Using points S and T -------(x,y)
S: y=4, x=2
T: y₂=8, x₂=6
Then insert into
Slope=y - y₂/ x-x₂
= 4 - 8/ 2-6
= -4/-4
= 1
The slope is one
Answer:
OptionC
Step-by-step explanation:
Let the point R and S form a line.
The slope of line RS would be
Change in y coordinate/change in x coordinate
=[tex]\frac{4-1}{2-(-1)} =1[/tex]
Now let us consider the line joining S and T
slope of line ST would be
=Change in y coordinate/change in x coordinate
=[tex]\frac{8-4}{6-2)} =1[/tex]
Thus we find the slopes of RS and ST are equal
Since parallel lines will have equal slopes, here S is the common point
So RS and ST have to be the same line.
Or the three points are collinear with slope = 1