Question

What are the factors of these two problems and how do you do the second one?
1. 32a^2 + 24b^2
2. 12a^2 –15ab –16a +20b

Answer 1

12a² –15ab –16a +20b = (12a² –15ab) –(16a -20b)

1st parenthesis : (12a² –15ab) = 3a(4a - 5b)

2nd parenthesis - (16a -20b) = - 4(4a -5b)

1st + 2nd = 3a(4a - 5b) - 4(4a -5b)

common factor (4a-5b) ==>hence  (4a=5b)(3a-4)