so hmmm we know 24 folks are coming over, and each are getting 1 box of peeps, 3 hot buns, and 1/3lb of ham
alrite, how much is that for 24 folks?
well, 24 boxes of peeps, 72 hotbuns and 8lbs of ham, we know the total for all those is 92.30 or 9230 in cents
let's say
p = price of peeps
b = price of hotbuns
h = price of lb of ham
so, thus then 24p + 72b + 8h = 9230
now, we know 12 "b" is 56 cents more than "p"
thus 12b = p + 56
we also know, a pound of ham is twice as "p + 12b" or h = 2(p + 12b)
thus [tex]\bf 24p+72b+8h=9230\quad
\begin{cases}
\underline{12b}=p+56\implies \boxed{b}=\cfrac{p+56}{12}\\\\
h=2(p+\underline{12b})\implies h=[2(p+p+56)]\\\\
\qquad h=2(2p+56)\implies h=4p+112
\end{cases}\\\\
-----------------------------\\\\
24p+72\left( \boxed{\cfrac{p+56}{12} }\right)+8(4p+112)=9230[/tex]
solve for "p"