Respuesta :
Given:
CS2 + 3O2 → CO2 + 2SO2
114 grams of CS2 are burned in an excess of O2
moles CS2 = 114 g/76.143 g/mol → 114g * mol/76.143 g = 1.497 mol
the ratio between CS2 and SO2 is 1 : 2
moles SO2 formed = 1.497 x 2 = 2.994 moles → 2nd option
CS2 + 3O2 → CO2 + 2SO2
114 grams of CS2 are burned in an excess of O2
moles CS2 = 114 g/76.143 g/mol → 114g * mol/76.143 g = 1.497 mol
the ratio between CS2 and SO2 is 1 : 2
moles SO2 formed = 1.497 x 2 = 2.994 moles → 2nd option