Respuesta :
To get a triplet : 13C1 * 4C3
To get a pair : 12C1 * 4C2
Total possibility = 52C5
P(full) = [(13C1 * 4C3) * 12C1 * 4C2] / 52C5
If my calculation is right, the P(full) =0.144%
To get a pair : 12C1 * 4C2
Total possibility = 52C5
P(full) = [(13C1 * 4C3) * 12C1 * 4C2] / 52C5
If my calculation is right, the P(full) =0.144%