Respuesta :
[tex]\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
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csc(\theta)=\cfrac{1}{sin(\theta)}
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\cfrac{1-sin^2(x)}{sin(x)-csc(x)}\implies \cfrac{cos^2(x)}{sin(x)-\frac{1}{sin(x)}}\implies \cfrac{cos^2(x)}{\frac{sin^2(x)-1}{sin(x)}}
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\cfrac{cos^2(x)}{1}\cdot \cfrac{sin(x)}{sin^2(x)-1}\implies \cfrac{cos^2(x)}{1}\cdot \cfrac{sin(x)}{-[1-sin^2(x)]}
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\cfrac{cos^2(x)sin^2(x)}{-cos^2(x)}\implies -sin(x)[/tex]
Re write the expression in maths terms:
(1-sin² x)/(sin x-csc x)
We know thar csc x =1/sin x. Replace: (1-sin² x)/(sin x-1/sin x)
= (1-sin² x)/[(sin² x-1 )/( sin x)]
= [(1-sin² x) .( sin x)]/(sin² x -1)===> -sin x
(1-sin² x)/(sin x-csc x)
We know thar csc x =1/sin x. Replace: (1-sin² x)/(sin x-1/sin x)
= (1-sin² x)/[(sin² x-1 )/( sin x)]
= [(1-sin² x) .( sin x)]/(sin² x -1)===> -sin x