93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0 C.what would be the volume of this dry gas at STP

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30-04-2017
Chemistry

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93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0 C.what would be the volume of this dry gas at STP

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BlueSky06 BlueSky06 · Answer 1 · 2017-05-13T10:42:26+02:00

Let us assume that the oxygen behaves as an ideal gas such that we can use the ideal gas equation to solve for the number of moles of O2.
PV = nRT ; n = PV/RT
Substituting the known values,
n = (0.930 atm)(93/1000 L) / (0.0821 L.atm/mol.K)(10 + 273.15K)
n = 3.72 x 10^-3 mols
At STP, the volume of each mol of gas is equal to 22.4 L.
volume = (3.73 x 10^-3 mols) x (22.4 L/1 mol)
volume = 0.0833 L or 83.34 mL