Well according to the Inscribed Angle Theorem, the angle inscribed in a circle is equal to one-half of its intercepted arc. We can apply that theorem to this problem as well. So the measure of AED = 1/2( arc AD + arc BC). Plug in the numbers and simplify.
AED = 1/2( 62 + 28)
AED = 1/2( 90 )
AED = 45
So the measure of angle AED is B. 45 degrees.
Hope I helped!
