Question

A spinner is divided into 4 equal size sections. The 4 sections are colored red green orange and blue. If Ana spins the spinner twice what are the possible outcomes?

Answer 1

there are 4 possible outcomes with the same colour:-
RR, OO, GG and BB.

The rest of the outcomes = number of permutations of 2 from 4 which is 

4*3*2*1 / 2 = 12   ( I am assuming that the order in which they appear does matter)

Soi the total ways = 12 + 4 = 16

Answer 2

Answer:

If you’re on I-ready the answer is

“ The spinner can land on the same color twice in a row, so there should be 16 possible outcomes”

Step-by-step explanation:

4 possible outcomes with the same color

RR, OO, GG and BB.

Total Ways = 12+4=16