Respuesta :

center: (5;0)
radius = 9

The center of the circle is required.

The radius is 9 units.

Center is at [tex](5,0)[/tex]

The equation of the circle is

[tex](x-5)^2+y^2=81[/tex]

The general equation of a circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where,

[tex](h,k)[/tex] = Center of circle

[tex]r[/tex] = Radius of circle

The given equation can also be written as

[tex](x-5)^2+(y-0)^2=9^2[/tex]

So, the radius is 9 units.

Center is at [tex](5,0)[/tex]

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