Respuesta :
9 2/3 written as an improper fraction, which I assume is what you mean, would be 29/3. Therefore, 3 would still be under the radical. I would say the answer is A, however, that's only based on the assumption that "simplest radical form" on your assignment also means written as an improper fraction.
Answer:
Option a - 3
Step-by-step explanation:
Given : Expression [tex]9^{\frac{2}{3}}[/tex]
To find :
The value remains under the radical.?
Solution :
We have to solve the expression in simpler form,
[tex]9^{\frac{2}{3}}[/tex]
We can re-write as,
[tex]=\sqrt[3]{9^2}[/tex]
[tex]=\sqrt[3]{81}[/tex]
[tex]=\sqrt[3]{3\times 3\times 3\times 3}[/tex]
[tex]=3\sqrt[3]{3}[/tex]
Therefore, The value remains under the radical is 3.
Hence, Option a is correct.