Respuesta :

9 2/3 written as an improper fraction, which I assume is what you mean, would be 29/3. Therefore, 3 would still be under the radical. I would say the answer is A, however, that's only based on the assumption that "simplest radical form" on your assignment also means written as an improper fraction.

Answer:

Option a - 3

Step-by-step explanation:

Given : Expression [tex]9^{\frac{2}{3}}[/tex]

To find :

The value remains under the radical.?

Solution :

We have to solve the expression in simpler form,

[tex]9^{\frac{2}{3}}[/tex]

We can re-write as,

[tex]=\sqrt[3]{9^2}[/tex]

[tex]=\sqrt[3]{81}[/tex]

[tex]=\sqrt[3]{3\times 3\times 3\times 3}[/tex]

[tex]=3\sqrt[3]{3}[/tex]

Therefore, The value remains under the radical is 3.

Hence, Option a is correct.

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