I think it's 9, because there is 4 for every 16 is 1/4.
And 36 can divide into 16, 2 times, so 32.
4*2 = 8
She would stop 8 times with 4 intersections left for
And since earlier we learned it's 1 for 4
The answer would be c) 9 intersections for 36.
Also after you get 8 you could just choose it by process of elimination because
3 is too small, you already have 8, 24 is too much, and it's very unlikely that all 4 of her remaining intersections had a stop because the rate is 1/4, so it couldn't be 12.
That's the way this should be solved.
Hope this helped
