Question

What is the value of x in this triangle?
Enter your answer as a decimal in the box. Round only
yOur final answer to the nearest hundredth. Show your work

Answer 1

for this type of problem I would use my trig functions. not sure if it is still taught this way but I learned the story of the "native American " SOH-CAH-TOA

This name is an acronym for the trig functions

SOH

sin (x) = opposit/hypotonusus

CAH

cos (x) = adjacent /hypotonusus

TOA

tan (x) = opposite /adjacent

so for this problem because of the sides you were given I would use cos (x) =adjacent /hypotonusus

so the setup is

cos (x) = 32/58

so

x = cos^-1 (32/58)

Answer 2

The value of x in the given triangle is equal to 33.4° if hypotenuse is 58 and perpendicular is 32.

What is trigonometric ratio?

Trigonometric ratios are the proportion of sides of a right angled triangle. sin, cos, tan, cosec, sec, cot are some of the trigonometric ratios. Sin is the ratio of perpendicular and hypotenuse, cos is the ratio of base and hypotenuse, tan is the ratio of perpendicular and base, cosec is the ratio of hypotenuse and perpendicular, sec is the ratio of hypotenuse and base, cot is the ratio of base and perpendicular.

How to find angle?

We have been given that the value of perpendicular that is 32, hypotenuse is 58 and x is the angle. We have to find the value of x.

sin x=32/58

sin x=0.55

x=$sin^{-1}(0.55)$

x=33.4°

Hence if the perpendicular is 32 and hypotenuse is 58 then the value of x is 33.4°.

Learn more about trigonometric ratios at https://brainly.com/question/24349828

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