Question

In 2010, the population of Sacramento, California, was 466,488. Sacramento's land area is about 97.9 square miles. To the nearest whole number, what was Sacramento's population density in 2010? Enter your answer in the box.

Answer 1

To solve this problem, divide the number of people by the amount of land. Then, round your answer to the nearest whole number since that is what the directions ask for. Your work should look like this:

466,488  /  97.9  =  4,764.94382

4,764.94382 is rounded to the nearest whole number as 4,765 

Your answer should be: 4,765

Answer 2

The correct answer is 4765 people per Mi^2