so hmm notice the picture below
thus [tex]\bf \cfrac{4.24}{x}=\cfrac{2x+5}{2x}\implies 8.48x=2x^2+5x\implies 8.48x-5x=2x^2
\\\\\\
3.48x=2x^2\implies 0=2x^2-3.48x\implies 0=x(2x-3.48)
\\\\\\
\begin{cases}
0=x\\
----------\\
0=2x-3.48\\
3.48=2x\\\\
\cfrac{3.48}{2}=x\\\\
1.74=x
\end{cases}[/tex]
so, is clearly not 0, so it has to be 1.74
