Question

Bob has a coin cup with four $1 tokens and two $5 tokens in it. He also has two $10 tokens and one $25 token in his pocket. He randomly draws a token from the cup, and then randomly draws a token from his pocket. What is the probability that he will draw $26 in tokens?

Answer 1

I would say 6/10 because there is two ten dollar coins in his pocket and that is greater than one.  He is probably going to draw a one dollar coin instead of of a five dollar coin because four is greater that two.

Answer 2

The probability that he will draw $26 in tokens is

How to find probability?

Probability of the event =  $\frac{required events}{all samples}$

• The probability of drawing token of $1 from coin cup is=4/6=2/3

• The probability of drawing token of $5 from coin cup is=2/6=1/3

• The probability of drawing token of $10 from his pocket is=2/3

• The probability of drawing token of $25 from his pocket is=1/3

Since only two tokens Bob can draw which must be equal to $26.

∴the possible combination is only $25+$1

By adding the probability of $25 and $1= 1/3×4/6

                                                                 ⇒2/9 answer.

What is probability?

The word "probability" is used to mean the chance that a particular event will occur expressed on a linear scale from 0 to 1, also expressed as a percentage between 0 and 100%.

Learn more about probability here: https://brainly.com/question/896456

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