Respuesta :
The domain is the set of numbers that the x value can be.
In an equation like [tex]y=x[/tex] the domain is all real numbers because x can be any number.
In the case of [tex]y = \sqrt{x+4} [/tex], any x value that is less than or equal to -4 will not work because you would be taking the square root of a negative number, which doesn't work unless you're graphing on a complex plane, which I assume you aren't.
Thus, the domain is [tex]x \geq -4[/tex]
I hope that helps!
In an equation like [tex]y=x[/tex] the domain is all real numbers because x can be any number.
In the case of [tex]y = \sqrt{x+4} [/tex], any x value that is less than or equal to -4 will not work because you would be taking the square root of a negative number, which doesn't work unless you're graphing on a complex plane, which I assume you aren't.
Thus, the domain is [tex]x \geq -4[/tex]
I hope that helps!
Answer:
[tex][-4,\infty)[/tex]
Step-by-step explanation:
We are asked to find the domain of of the function [tex]y=\sqrt{x+4}[/tex].
We know that domain of a square root function is not defined for negative values, so we can set an inequality to find the domain of our given function as:
[tex]x+4\geq 0[/tex]
[tex]x+4-4\geq 0-4[/tex]
[tex]x\geq -4[/tex]
Therefore, the domain of our given function is values of x greater than or equal to [tex]-4[/tex], that is [tex][-4,\infty)[/tex]