Answer: The gas needs to be cooled down to 76.15 K
Explanation:
To calculate the temperature of the gas, we use the equation given by ideal gas, which is:
[tex]PV=nRT[/tex]
where,
P = Pressure of the gas = 253.25 kPa
V = Volume of the gas = 0.25 L
n = Number of moles of gas = 0.10 mol
R = Gas constant = [tex]8.314\text{ L kPa }K^{-1}mol^{-1}[/tex]
T = Temperature of the gas = ? K
Putting values in above equation, we get:
[tex]253.25kPa\times 0.25L=0.10mol\times 8.314\text{ L kPa }K^{-1}mol^{-1}\times T\\\\T=76.15K[/tex]
Hence, the gas needs to be cooled down to 76.15 K
