Question

What is the electric force acting between two charges of −0.0085 C and −0.0025 C that are 0.0020 m apart?

Answer 1

Answer:

4.8•10^10 N

Explanation:

(9.00•10^9)(-0.0085)(-0.0025)

————————————————= 4.8•10^10

0.0020^2

Answer 2

The electric force acting between two charges of −0.0085 C and −0.0025 C that are 0.0020 m apart is

What is electric force?

The repulsive or attractive interaction between any two charged bodies is called as an electric force.

$F_{e} = k_{e} \frac{q_{1} q_{2} }{r^{2} }$

$F_{e} = 8.987*10^{9} \frac{0.0085* 0.0025 }{0.0020^{2} }$

$F_{e} = 4.78*10^{10} N$

To learn more about electric force here

https://brainly.com/question/2526815

#SPJ2