Respuesta :

4y + 1 = 13

first you need to get rid of the 1 by -1

4y = 13 - 1

which is

4y = 12

then divide by 4

you get

y = 3
[tex]4y +1 =13[/tex]

subtract 1 to both sides

[tex]4y +1 -1 = 13 -1 4y=12[/tex]

divide by 4 to both sides
[tex]4y / 4 = 12/4 y=3[/tex]

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