Respuesta :
Is x2, [tex] x^{2} [/tex] or 2x?
If it is [tex] x^{2} [/tex] then:
(x - 5)(x - 5)
[tex] x^{2} [/tex] - 5x - 5x + 25
[tex] x^{2} [/tex] - 10x + 25
x - 5 = 0
x = 5
If it is [tex] x^{2} [/tex] then:
(x - 5)(x - 5)
[tex] x^{2} [/tex] - 5x - 5x + 25
[tex] x^{2} [/tex] - 10x + 25
x - 5 = 0
x = 5