Question

A swimmer runs over a horizontal diving board at a speed of 0.95 meters/second. 2.0 seconds after she dives, she hits the water. What was the height of the diving board from the water's surface and how far from the board was the swimmer when she hit the water?

Answer 1

horizontal velocity(Uh)=0.95 m/s 
t=2s 
vertical velocity(Uv)=0 
taking vertical motion 
h=Uv*t+0.5gt^2 
h=0.5gt^2=20 m 
height of diving board is 20 m 

range=u*t=0.95*2=1.9 m 
so she hit the water 1.9 m away fron the board