Question

How do I write a rule for the nth term of the sequence?

Answer 1

easy
an=a1+d(n-1)
for the top one
d=4 and a14=46
a14=a1+4(14-1)
a14=a1+4(13
46=a1+52
-6=a
an=-6+4(n-1)



bottom one
d=-6
a12=-4
a12=a1-6(12-1)
-4=a1-6(11)
-4=a1-66
62=a1
an=62-6(n-1)