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What is the pOH of a solution with [OH-] = 2.0 10-2?

A. 2.00 B. -1.70 C. 3.01 D. 1.70

Respuesta :

its 1.70 for apex not negative

The pOH of a solution with [OH-] = 2.0 10-2 is D.1.70.

pH=−log10[H+]=−log10(4.8×10−10)=−(−9.32)=+9.32

How do you find the pOH value?

To find the pOH, simply subtract the pH from 14. In order to calculate the pOH, take the negative log of the hydroxide ion concentration. To find the pH, simply subtract pOH from 14.

if you realize pH, it is clean to calculate pOH due to the fact pH + pOH = 14. on occasion, you want to calculate pOH from the hydroxide ion attention [OH-]. you may need a calculator here, the use of the equation pOH = -log[OH-].

in which [OH−] is the hydroxide ion awareness of the solution in M or mol⋅dm−three, moles in step with cubic decimeter, or equivalently moles in line with liter. Substituting [OH−]=1.36⋅10−10 mol⋅dm−three, pOH=9.866.

Learn more about pOH here: https://brainly.com/question/13557815

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