Question

what is the x-cordinate of the vertex? y=x^2+2x+1

Answer 1

for
y=ax^2+bx+c
the x value of the vertex is -b/(2a)
given

y=1x^2+2x+1
a=1
b=2
-b/2a=-2/(2*1)=-2/2=-1
the x coordinate is x=-1