Question

The double-replacement reaction of sulfuric acid with aluminum hydroxide produces aluminum sulfate salt and water. Balance this skeleton equation, then determine the mole ratio of H2SO4:H2O. H2SO4 + Al(OH)3 Al2(SO4)3 + H2O? (how do i determine the mole ration? please help)
A) 1:1
B) 2:3
C) 3:1
D) 3:6
E) 6:3

Answer 1

We are given that the reaction is a double-replacement reaction with reactants H2SO4 and Al(OH)3

The balanced chemical reaction is
3 H2SO4 + 2 Al(OH)3 ---> Al2(SO4)3 + 6 H2O

Therefore, the ratio of H2SO4:H2O is
D) 3:6

Answer 2

Answer: D) 3:6

Explanation: $H_2SO_4+Al(OH)_3\rightarrow Al_2(SO_4)_3+H_2O$

This is a double displacement reaction in which exchange of ions take place.

According to the law of conservation of mass, mass is neither created nor destroyed. Thus the mass of products must be equal to the mass of reactants.The number of atoms of each element must be same on both sides of the reaction.Thus the equation is balanced.

The balanced chemical equation is:

$3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O$

The mole ratio of $H_2SO_4:H_2O$ is 3:6.